A student measures the potential difference across a resistor using two different voltmeters:
State the absolute uncertainty for each reading.
Voltmeter A (Analogue): ±0.1 V
Voltmeter B (Digital): ±0.01 V
A wire diameter is measured 5 times with a micrometer:
0.24 mm, 0.26 mm, 0.23 mm, 0.29 mm, 0.25 mm.
Calculate the mean diameter and its absolute uncertainty.
Mean: (0.24+0.26+0.23+0.29+0.25) / 5 = 0.25 mm (to 2 s.f.)
Uncertainty: ±0.03 mm
Final Answer: 0.25 ± 0.03 mm
The force on an object is F = 20 ± 1 N and the distance moved is d = 5.0 ± 0.2 m.
Calculate the work done (W = F × d) and the absolute uncertainty in the work done.
Step 1: Calculate Value
W = 20 × 5.0 = 100 J
Step 2: Calculate % Uncertainties
% in F = (1/20) × 100 = 5%
% in d = (0.2/5.0) × 100 = 4%
Step 3: Add % Uncertainties (Multiplication Rule)
Total % Uncertainty = 5% + 4% = 9%
Step 4: Convert back to Absolute
9% of 100 J = 9 J
Final Answer: 100 ± 9 J
The radius of a circle is measured as r = 4.0 ± 5%.
Calculate the percentage uncertainty in the Area (A = πr²).
Answer: 10%
Note: Constants like π have zero uncertainty.
A student plots a graph of Force vs. Acceleration. They draw a Line of Best Fit (LOBF) and a Line of Worst Fit (LOWF) passing through the error bars.
Calculate the percentage uncertainty in the gradient.
Answer: 6.25%
Calculation: (|2.40 - 2.55| / 2.40) × 100
= (0.15 / 2.40) × 100 = 6.25%